**Let’s** examine the **number of bars and the number of musses** together with the meanings of the units in detail from the technical point of view.

*Bar:* Pressure unit defined as 100,000 Pa.Approximately equal to the atmospheric pressure at sea level. It can be used in engineering applications because Pascal has very high values.A pressure of 0,1 N applied to a surface of 1 cm ² results in a vertically effective conclusion.

1 bar = 10 ^ 5 Pa

*mSS:* Vertical effect of the water column at a height of 1 meter and pressure on the surface. 1 mSS water pressure varies according to water density in water temperature direction.

## How many bars does one bar have? Formulas to use for the question

– Pressure is the amount of steep force acting on a surface per unit area. Solids, liquids and gases apply a force to the surface due to their weight. Regardless of the source of force, the force (P) acting perpendicularly to the surface of the unit is called the pressure force (F) of the force acting perpendicularly to the whole surface.

P = F / A P: Pressure, F: Force, A: Area

Force is the effect that gives a massive motion in Physics. A force with both direction and magnitude is a vector quantity. According to the second law of Newton, an object with constant mass accelerates in inverse proportion to the net mass applied on it. The net force applied to an object is equal to the time dependent change in momentum of the cismin.

F = m × g for m: Mass, g: Gravity acceleration

– The mass is the amount of matter that a substance possesses, the volume where a substance covers the space, and the mass is the mass of a unit mass of a substance.

For d = m × V d: Mass, m: Mass V: Volume

For V = A × h, A: Area, h: Height

### How many bars does one bar have? Sorusun’s Answer

Combining the formulas P = F / A and F = m × g is P = m × g / A.

Combining the formulas m = d x V and p = m x g / A is P = d x V x g / A.

Combining the formulas V = A × h and P = d × V × g / A is P = d × A × h × g / A and when A is simplified, the formula P = d × h × g appears.

In this direction;

P = d × h × g = Density (kg / m³) × Height (m) × Gravity acceleration (m / s²) = kg / m.s² = Pa.

Water density at 0 C temperature 1000 kg / m³, gravity acceleration 9,80665 m / s² 1 m high water pressure: P = d × h × g = 1000 × 1 × 9,80665 = 9806,65 Pa resultant output.

1 bar = 10 ^ 5 Pa and the pressure of 1 m high water is 9806,65 Pa, 9806,65 / 100000 = 0,0980665 bar. 0,0980665 bar is 1 mSS and 1 bar is 1 / 0,0980665 = 10,197,162 … mSS.

The result is 1 bar = 10,197 … mSS. In practice, 1 bar is used as 10 mSS.